Question

I am hoping to receive help getting started with this problem, possibly some steps in the correct direction.

Here is the question: 5.0mLs of a 6.0M solution of HCl was transferred to a 1000ml volumetric flask and diluted to volume w/ water. 50mLs of this solution was then transferred to a 100mL flask and diluted to Volume with water. What is the molarity of the 2nd diluted solution?

Answer 1

Can some one check to see if I did this correct:

6M= moles of solute/.005 L solution

.03=moles solute

M of2nd solu=.03 m solute/.05L solution

M=.6

Answer 2

After the second dilution:
M of2nd solu=.03 m solute/<b>.10L</b> solution

Answer 3

Why .10L

Answer 4

I based on this, unless I mis-read it.

<i>50mLs of this solution was then transferred to a 100mL flask and diluted to Volume with water...</i>

Answer 5

Sorry, the second post was sent by mistake. No shouting intended! :)