Question
A 65 kg diver stands still on a tower, 10.0 m above the water.
Answers
GPT 3.5
The weight of the diver is given by the equation W = mg, where m is the mass of the diver and g is the acceleration due to gravity.
Substituting the given values, we have W = (65 kg)(9.8 m/s²) = 637 N.
The work done by the diver to stay still on the tower is equal to the force applied multiplied by the distance moved. In this case, the distance moved is 0 since the diver is standing still. Therefore, the work done is 0 J.
The potential energy of the diver (PE) is given by the equation PE = mgh, where m is the mass of the diver, g is the acceleration due to gravity, and h is the height of the tower above the water.
Substituting the given values, we have PE = (65 kg)(9.8 m/s²)(10.0 m) = 6370 J.
Thus, the potential energy of the diver while standing still on the tower is 6370 J.
Substituting the given values, we have W = (65 kg)(9.8 m/s²) = 637 N.
The work done by the diver to stay still on the tower is equal to the force applied multiplied by the distance moved. In this case, the distance moved is 0 since the diver is standing still. Therefore, the work done is 0 J.
The potential energy of the diver (PE) is given by the equation PE = mgh, where m is the mass of the diver, g is the acceleration due to gravity, and h is the height of the tower above the water.
Substituting the given values, we have PE = (65 kg)(9.8 m/s²)(10.0 m) = 6370 J.
Thus, the potential energy of the diver while standing still on the tower is 6370 J.