Solve the system of equations.−6x+2y=−32 4x+3y=−9

Answer 1

To solve the system of equations:
-6x + 2y = -32   (Equation 1)
4x + 3y = -9   (Equation 2)

We can use the method of elimination. Multiply Equation 1 by 2 and Equation 2 by 3 to make the coefficient of "y" in both equations the same:

-12x + 4y = -64   (Equation 3)
12x + 9y = -27   (Equation 4)

Add Equations 3 and 4 together:

-12x + 4y + 12x + 9y = -64 - 27
13y = -91

Divide both sides by 13:

y = -7

Substitute this value of y back into Equation 1:

-6x + 2(-7) = -32
-6x - 14 = -32
-6x = -32 + 14
-6x = -18
x = 3

The solution to the system of equations is x = 3 and y = -7.

Answer 2

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