The slope-intercept form of a linear equation is y = mx + b, where m represents the slope and b represents the y-intercept.
Given a slope of 4 and a point (-2,-5), we can substitute the values into the equation y = mx + b to find the value of b.
-5 = 4*(-2) + b
-5 = -8 + b
To solve for b, we add 8 to both sides:
b = -5 + 8
b = 3
Now we substitute the values of m = 4 and b = 3 back into the equation:
y = 4x + 3
To convert this equation into standard form, we rearrange it to have all the terms on one side:
4x - y = -3
Therefore, the equation of the line in standard form with a slope of 4 passing through the point (-2,-5) is 4x - y = -3.
Write an equation of the line in standard form given the slope through the given point:
slope = 4, (-2,-5)
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