Asked by Rachel
If a group of data has a mean of 19 and a standard deviation of 77.8, what is the interval that should contain at least 88.9% of the data?
Answers
Answered by
MathMate
Assuming a normal distribution.
If the interval contains 88.9% of the data, we can look up the normal distribution table:
http://cazelais.disted.camosun.bc.ca/264/normal_table.pdf
we find that the half-interval that contains 44.45% of the data is at 1.6σ from the mean.
We extend the interval to both sides of the mean to obtain 88.9% coverage.
Thus, the required interval is
[μ-1.6σ , μ+1.6σ]
where
μ = mean = 19
σ = standard deviation = 77.8
If the interval contains 88.9% of the data, we can look up the normal distribution table:
http://cazelais.disted.camosun.bc.ca/264/normal_table.pdf
we find that the half-interval that contains 44.45% of the data is at 1.6σ from the mean.
We extend the interval to both sides of the mean to obtain 88.9% coverage.
Thus, the required interval is
[μ-1.6σ , μ+1.6σ]
where
μ = mean = 19
σ = standard deviation = 77.8
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.