Starting from 50 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 30 miles per hour.

Question

The distance of the car from the checkpoint is given by `d=\left|50=30t\right|.`

At what times is the car 5 miles from the checkpoint?

Answer 1

To find the times when the car is 5 miles from the checkpoint, we can substitute d = 5 into the equation and solve for t.

5 = |50 - 30t|

Since the expression inside the absolute value signs can only be positive, we have:

5 = 50 - 30t

Subtracting 50 from both sides, we get:

-45 = -30t

Dividing both sides by -30, we have:

t = 1.5

Therefore, the car is 5 miles from the checkpoint at times t = 1.5 hours.

Answer 2

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Answer 4

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