I assume your actual yield is 6.7496 g AgCl.
Theoretical yield:
AgNO3 + NaCl ==> AgCl + NaNO3.
Convert AgNO3 to moles. moles = g/molar mass.
Convert NaCl to moles.
Now you must determine which reagent (AgNO3 or NaCl0 is in excess. Since the reaction shows a 1:1 ratio for moles AgNO3 vs moles NaCl, the one with the fewer moles will be the limiting reagent. My guess is that will be AgNO3.
Then convert moles AgNO3 to moles AgCl and go from there to grams AgCl. That will be the theoretical yield. I did a quick calculation (but you need to check it out) and came out with about 3.4 g AgCl as theoretical yield. If I didn't goof, then you have something extra in your product for you have over 100% yeild and that's a no, no. My guess would be you didn't wash all of the NaNO3 and excess NaCl out of the product.