Question

Cindy won $50.00 for getting first place in the Science Fair. She spent her winnings on robotics kits and chemistry sets. Each robotics kit (y) costs $10.00, while each chemistry set costs $8.00 (x). Which of the following is a viable solution to the number of robotics kits and chemistry sets Cindy can purchase, assuming she spends her entire winnings?(1 point)
Responses

(0,5)
left parenthesis 0 comma 5 right parenthesis

(5,1)
left parenthesis 5 comma 1 right parenthesis

(3,2.6)
left parenthesis 3 comma 2.6 right parenthesis

(−5,9)

Answer 1

thats not correct

Answer 2

To find the viable solution, we need to determine how many robotics kits (y) and chemistry sets (x) Cindy can purchase with her $50 winnings.

Let y represent the number of robotics kits and x represent the number of chemistry sets.

Each robotics kit costs $10, so Cindy can purchase y/10 kits.
Each chemistry set costs $8, so Cindy can purchase x/8 sets.

Since Cindy spends her entire $50 winnings, we know that the total cost of the kits and sets must be $50.

So, the equation for the total cost is: (y/10) + (x/8) = 50.

To find the viable solution, we need to find a combination of y and x that satisfies this equation.

Now let's check each option:

(0,5):
For y = 0 and x = 5, we have (0/10) + (5/8) = 0 + 10/8 = 1.25, which is not equal to 50. So, this option is not a viable solution.

(5,1):
For y = 5 and x = 1, we have (5/10) + (1/8) = 0.5 + 0.125 = 0.625, which is not equal to 50. So, this option is not a viable solution.

(3,2.6):
For y = 3 and x = 2.6, we have (3/10) + (2.6/8) = 0.3 + 0.325 = 0.625, which is not equal to 50. So, this option is not a viable solution.

(-5,9):
This option has a negative value for y, which does not make sense in the context of the problem. So, this option is not a viable solution.

Therefore, the correct answer is none of the given options.

Answer 3

Apologies for the incorrect response. Let's reevaluate the given options.

Option (0,5):
For y = 0 and x = 5, the equation becomes (0/10) + (5/8) = 0 + 0.625 = 0.625, which is not equal to 50. So, this option is not a viable solution.

Option (5,1):
For y = 5 and x = 1, the equation becomes (5/10) + (1/8) = 0.5 + 0.125 = 0.625, which is not equal to 50. So, this option is not a viable solution.

Option (3,2.6):
For y = 3 and x = 2.6, the equation becomes (3/10) + (2.6/8) = 0.3 + 0.325 = 0.625, which is not equal to 50. So, this option is not a viable solution.

Option (-5,9):
This option has a negative value for y, which does not make sense in the context of the problem. So, this option is not a viable solution.

Based on this reevaluation, it appears that none of the given options is a viable solution. I apologize for any confusion caused.