Question

5. Concentration of 0.24L KMnO4 solution required to oxidize 2.7g of Oxalic Acid??? 5H2C2O4 (aq) + 6H+ + 2MnO4- (aq) --> 10CO2 (g) + 2 Mn2+(aq) +8H20 (l)



4.How many grams of calcium chloride can be prepared if a student uses 500g if calcium carbonate and 2.00L of a 4.00 Mol/L sodium chloride solution in the reaction.??
CaCO3 + 2HCl -> CaCl2 + H2O



8. 2(NH4)3PO4-->3N2+O2+12H2+2PO3

a)name products
b)Name the reactant
c)type of reaction

Answer 1

5. Concentration of 0.24L KMnO4 solution required to oxidize 2.7g of Oxalic Acid??? <b>5</b>H2C2O4 (aq) + 6H+ + <b>2</b>MnO4- (aq) --> 10CO2 (g) + 2 Mn2+(aq) +8H20 (l)

Molecular weight:
H2C2O4 = 2+24+64 = 90
2.7 g of oxalic acid is equivalent to
2.7/90=0.03 mole

Number of moles of KMnO⁴ required
=0.03*2/5=0.012 mole

let x=Concentration of KMnO⁴
then 0.24 l * x mole/l =0.012 mole
x=0.05 mole/l.


4.How many grams of calcium chloride can be prepared if a student uses 500g if calcium carbonate and 2.00L of a 4.00 Mol/L sodium chloride solution <b>(Hydrochloric acid)</b> in the reaction.??
CaCO3 + 2HCl -> CaCl2 + H2O

Molecular weight of calcium carbonate
= 40+12+48 = 100
500 g. = 500/100= 5 moles
HCl required for complete reaction with calcium carbonate
= 5*2/1=10 moles

Actual quantity of HCl used
=2 l. * 4 mol/l
=8 moles

Thus number of moles of CaCl₂ produced
= 5*8/10=4
Weight of CaCl₂ produced
= 4*(40+2*35.5)=444 g.

Answer 2

Thanks man!!!could u also help me out on #8 thank you sooo much!!

Answer 3

I would like to, but I am not sure under what conditions the reaction indicated in #8 will take place. It involves the dissociation of ammonia into nitrogen and hydrogen. Do you have the source of the equation?

Answer 4

tht is the only info that is given .i don't know wat to do//u helped me on a question yestesday #3 i think u forgot to use STP for that one u, can go and check it over///thanks

Answer 5

#3.
The problem is the question.
Water vapour calculated was for STP.

However, if it was pure water vapour, it would condense to form water, and does not exist any more in vapour form.

On the other hand, if this amount is dissipated in the air as humidity, it can exist at STP.

Answer 6

8. 2(NH4)3PO4-->3N2+O2+12H2+2PO3
I believe the equation is not exact or not complete.
The left hand side is ammonium triphosphate.
The right hand side is not clear to me if it is nitrogen, oxygen, H⁺ and PO₃³⁺ ions, but they do not balance.

Answer 7

they asked to name the products and type of reaction

Answer 8

tht is all that is given..i don't know
they asked to name the products and type of reaction//thanks