A tennis player hits a 0.1-kilogram tennis ball, with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis players opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?

A. 6.5 N
B. 7.5 N
C. 0.01 N
D. 1 N

1 answer

To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force equals mass times acceleration (F=ma).

The mass of the tennis ball is 0.1 kilograms.

The acceleration of the ball is 10 meters per second squared.

Therefore, the force exerted by the floor on the ball is:

F = ma
= 0.1 kg * 10 m/s^2
= 1 N

So, the floor exerted 1 N of force on the ball.

Therefore, the correct answer is option D. 1 N.