The set, denoted as A, with the single element of 2/3 is {2/3}.
Any subset of A can be an empty set, {2/3}, or both combined.
Any subset of A can be an empty set, {2/3}, or both combined.
enter number 1: rational numbers, integers,whole numbers, natural numbers.
enter number 2: rational numbers, integers, whole numbers.
enter number 3: rational numbers, integers. enter number 4: rational numbers.
enter number 5: irrational numbers.
(3/4) + (-11/4) = (3 - 11)/4 = -8/4
The answer, -8/4, can be simplified to its lowest terms by dividing both the numerator and denominator by their greatest common divisor, which is 4:
(-8/4) ÷ 4/4 = -2/1 = -2
Therefore, the sum of 3/4 and -11/4, reduced to lowest terms, is -2.
13 degrees Celsius - 18.6 degrees Celsius = -5.6 degrees Celsius
Therefore, the temperature now is -5.6 degrees Celsius.
So, we can rewrite the expression as follows:
-492.89 + 871.78
= 378.89
Therefore, the result is 378.89.
|-18.26 - (-2.45)| = |-18.26 + 2.45|
= |-15.81|
= 15.81
Therefore, the distance between -18.26 and -2.45 on a number line is 15.81.
24 - (-15) = 24 + 15
= 39
Therefore, the result is 39.
17 4/9 = (17 * 9 + 4)/9 = 157/9
Now we can rewrite the expression as follows:
157/9 + 5/9 - 8 - 10
Combining like terms, we get:
(157 + 5)/9 - 18
= 162/9 - 18
To subtract fractions, we need a common denominator, which in this case is 9. So we rewrite 18 as 162/9:
162/9 - 162/9
Now, we can subtract the numerators:
(162 - 162)/9
= 0/9
Finally, we simplify the fraction:
0/9 = 0
Therefore, the result is 0.
Final temperature - Initial temperature = Change in temperature
-1.6 degrees Celsius - (-5.8 degrees Celsius) = Change in temperature
To simplify the calculation, we can rewrite the subtraction as addition by taking the additive inverse of -5.8 degrees Celsius:
-1.6 degrees Celsius + 5.8 degrees Celsius = Change in temperature
= 4.2 degrees Celsius
Therefore, the change in temperature during the three hours is 4.2 degrees Celsius.
This means that the temperature increased by 4.2 degrees Celsius from -5.8 degrees Celsius at 9 a.m. to -1.6 degrees Celsius at noon.