Asked by Joackim Patrick
In triangle XYZ, Side X=16cm , side Y=14cm and side Z=15cm . Calculate the size of angle X to the nearest degrees and minute?
Answers
There are no human answers yet.
Answered by
GPT 3.5
To find the size of angle X, we can use the Law of Cosines.
The Law of Cosines states that in a triangle with sides a, b, and c, and angle C opposite side c:
c^2 = a^2 + b^2 - 2ab*cos(C)
Applying this formula to triangle XYZ, where side X = 16cm, side Y = 14cm, and side Z = 15cm, we can solve for angle X.
Plugging in the values, we have:
16^2 = 14^2 + 15^2 - 2*14*15*cos(X)
Simplifying:
256 = 196 + 225 - 420*cos(X)
256 = 421 - 420*cos(X)
Rearranging to isolate cos(X):
420*cos(X) = 421 - 256
420*cos(X) = 165
cos(X) = 165/420
cos(X) = 0.392857
To find X, we take the inverse cosine (arc cosine) of 0.392857:
X = acos(0.392857)
X ≈ 67.52 degrees
To convert this to degrees and minutes, we know that there are 60 minutes in one degree. Therefore:
0.52 degrees = 0.52 * 60 = 31.2 minutes
So, the size of angle X is approximately 67 degrees and 31 minutes.
The Law of Cosines states that in a triangle with sides a, b, and c, and angle C opposite side c:
c^2 = a^2 + b^2 - 2ab*cos(C)
Applying this formula to triangle XYZ, where side X = 16cm, side Y = 14cm, and side Z = 15cm, we can solve for angle X.
Plugging in the values, we have:
16^2 = 14^2 + 15^2 - 2*14*15*cos(X)
Simplifying:
256 = 196 + 225 - 420*cos(X)
256 = 421 - 420*cos(X)
Rearranging to isolate cos(X):
420*cos(X) = 421 - 256
420*cos(X) = 165
cos(X) = 165/420
cos(X) = 0.392857
To find X, we take the inverse cosine (arc cosine) of 0.392857:
X = acos(0.392857)
X ≈ 67.52 degrees
To convert this to degrees and minutes, we know that there are 60 minutes in one degree. Therefore:
0.52 degrees = 0.52 * 60 = 31.2 minutes
So, the size of angle X is approximately 67 degrees and 31 minutes.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.