Subtract 7√^- 5−4√^- 5.(1 point)
The difference is
3 answers
7√^- 5 - 4√^- 5 is equal to 0.
thats wrong
I apologize for the mistake. Let's redo the calculation:
Given:
7√^-5 - 4√^-5
We can simplify the expression by using the property of exponents: √a = a^(1/2).
7√^-5 can be written as 7*(√-1/5) = 7*(-1/5)^(1/2).
Similarly, 4√^-5 can be written as 4*(-1/5)^(1/2).
Now, let's simplify further:
7*(-1/5)^(1/2) - 4*(-1/5)^(1/2)
Since (-1/5)^(1/2) represents the square root of -1/5, which is a complex number, there is no real number difference for this expression.
Therefore, the difference is undefined or non-real.
Given:
7√^-5 - 4√^-5
We can simplify the expression by using the property of exponents: √a = a^(1/2).
7√^-5 can be written as 7*(√-1/5) = 7*(-1/5)^(1/2).
Similarly, 4√^-5 can be written as 4*(-1/5)^(1/2).
Now, let's simplify further:
7*(-1/5)^(1/2) - 4*(-1/5)^(1/2)
Since (-1/5)^(1/2) represents the square root of -1/5, which is a complex number, there is no real number difference for this expression.
Therefore, the difference is undefined or non-real.