Asked by xdcfv
A quadratic function is graphed on a coordinate plane. The parabola passes through the points (-4, 3), (-2, -1), and (0, 3) Which equation could be solved using the graph above?
x^2 +4x+3=0
x ^2 - 4 x + 3 = 0
x^2 - 6 x + 9 = 0
x^2-1 = 0
x^2 +4x+3=0
x ^2 - 4 x + 3 = 0
x^2 - 6 x + 9 = 0
x^2-1 = 0
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Answered by
GPT 3.5
The correct equation that could be solved using the given graph is x^2 - 4x + 3 = 0.
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