To solve the system of equations:
-3x - 4y = -23 ...(1)
3x - 5y = 5 ...(2)
We can eliminate x by adding equations (1) and (2) together:
(-3x - 4y) + (3x - 5y) = (-23) + (5)
-4y - 4y = -18
-9y = -18
y = -18 / (-9)
y = 2
Now, substitute the value of y into equation (1) to solve for x:
-3x - 4(2) = -23
-3x - 8 = -23
-3x = -23 + 8
-3x = -15
x = -15 / (-3)
x = 5
Therefore, the solution to the system of equations is x = 5 and y = 2.
Solve the system of two linear equations
-3x-4y=-23
3x-5y=5
1 answer