To solve this system of equations, we can use the method of elimination or substitution.
Let's solve it using the method of elimination.
We start by multiplying both sides of the second equation by 2 to make the coefficients of x in both equations the same:
2(2x-4y) = 2(-16)
4x-8y = -32
Now, we can subtract the second equation from the first equation to eliminate x:
(2x+8y) - (4x-8y) = 8 - (-32)
-2x + 16y = 40
Now, we have the following system of equations:
-2x + 16y = 40
2x + 8y = 8
Adding the equations together, we get:
-2x + 16y + 2x + 8y = 40 + 8
24y = 48
y = 48/24
y = 2
Substituting y = 2 in either of the original equations, we can find x:
2x + 8(2) = 8
2x + 16 = 8
2x = -8
x = -4
Therefore, the solution to the system of equations is x = -4 and y = 2.
Solve the system of equations
2x+8y=8
2x-4y=-16
1 answer