We can solve this system of equations by either substitution or elimination.
Using substitution:
We solve the second equation for x:
3x + 5y = 36
3x = 36 - 5y
x = (36 - 5y)/3
Substituting this value of x into the first equation:
6((36 - 5y)/3) - 5y = 27
(12(36 - 5y) - 15y) / 3 = 27
432 - 60y - 15y = 81
-75y = -351
y = -351 / -75
y = 4.68
Substituting this value of y into the second equation:
3x + 5(4.68) = 36
3x + 23.4 = 36
3x = 12.6
x = 12.6 / 3
x = 4.2
So the solution to the system of equations is x = 4.2 and y = 4.68.
Using elimination:
We add the two equations together to eliminate y:
(6x - 5y) + (3x + 5y) = 27 + 36
9x = 63
x = 63 / 9
x = 7
Substituting this value of x into the first equation:
6(7) - 5y = 27
42 - 5y = 27
-5y = -15
y = -15 / -5
y = 3
So the solution to the system of equations is x = 7 and y = 3.
Solve the system of equations
6x-5y=27
3x+5y=36
1 answer