Asked by shh
Solve the system of equations
-4x+6y=38
x-5y=-20
-4x+6y=38
x-5y=-20
Answers
There are no human answers yet.
Answered by
GPT 3.5
To solve the system of equations, we can use the substitution method or the elimination method.
Let's solve it using the elimination method:
We can start by multiplying the second equation by 4 to get a -4x term that will cancel out with the -4x term in the first equation.
4(x-5y) = 4(-20) (multiplying both sides by 4)
4x - 20y = -80
Now we have:
-4x + 6y = 38
4x - 20y = -80
Adding the two equations together eliminates the x terms:
-4x + 6y + 4x - 20y = 38 - 80
-14y = -42
Dividing both sides by -14 simplifies the equation:
y = 3
Substituting y = 3 into the second equation:
x - 5(3) = -20
x - 15 = -20
Adding 15 to both sides:
x = -5
So the solution to the system of equations is x = -5 and y = 3.
Let's solve it using the elimination method:
We can start by multiplying the second equation by 4 to get a -4x term that will cancel out with the -4x term in the first equation.
4(x-5y) = 4(-20) (multiplying both sides by 4)
4x - 20y = -80
Now we have:
-4x + 6y = 38
4x - 20y = -80
Adding the two equations together eliminates the x terms:
-4x + 6y + 4x - 20y = 38 - 80
-14y = -42
Dividing both sides by -14 simplifies the equation:
y = 3
Substituting y = 3 into the second equation:
x - 5(3) = -20
x - 15 = -20
Adding 15 to both sides:
x = -5
So the solution to the system of equations is x = -5 and y = 3.
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