Question

Solve the system of equations
8x-3y=-22
y=10+4x

Answer 1

To solve the system of equations, we can substitute the value of y from the second equation into the first equation.

Substituting y=10+4x into the first equation, we get:

8x - 3(10+4x) = -22

Simplifying, we have:

8x - 30 - 12x = -22

Combining like terms, we get:

-4x - 30 = -22

Adding 30 to both sides:

-4x = 8

Dividing both sides by -4:

x = -2

Substituting this value of x into the second equation to find y:

y = 10 + 4(-2)
y = 10 - 8
y = 2

Therefore, the solution to the system of equations is x = -2 and y = 2.