Question

When 1.000 mole of ammonia reacts with oxygen, the enthalpy change for the reaction is –906 kJ.The balanced chemical equation for this reaction is

a) 4NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 960 kJ
b) 2NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 480 kJ
c) 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) △H = –480 kJ
d) NH3(g) + 5/4 O2(g) → NO(g) + 3/2 H2O(g) △H = –240 kJ
e) NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 240 kJ
Answer
are you sure?
Answer
what is the correct answer?
Answer
are you sure it's a)?
Answer
are you sure it's b)?
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