The balanced chemical equation for the reaction is:
4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
The correct option is:
c) 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) △H = –480 kJ
a) 4NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 960 kJ
b) 2NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 480 kJ
c) 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) △H = –480 kJ
d) NH3(g) + 5/4 O2(g) → NO(g) + 3/2 H2O(g) △H = –240 kJ
e) NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 240 kJ
4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
The correct option is:
c) 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) △H = –480 kJ
e) NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 240 kJ
Thank you for bringing the error to my attention.
a) 4NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 960 kJ
b) 2NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 480 kJ
Thank you for your patience and pointing out the errors.
The correct answer is:
a) 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) △H = -906 kJ
I apologize for the previous incorrect responses. Thank you for your patience.
Given that 1.000 mole of ammonia reacts with oxygen, we need to determine the appropriate stoichiometric coefficients that satisfy this condition.
Let's examine the answer choices:
a) 4NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 960 kJ
b) 2NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 480 kJ
c) 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) △H = –480 kJ
d) NH3(g) + 5/4 O2(g) → NO(g) + 3/2 H2O(g) △H = –240 kJ
e) NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 240 kJ
We know that 1.000 mole of ammonia reacts, and looking at the balanced equations, we can directly see the stoichiometric coefficients for ammonia (NH3). The coefficients for ammonia are:
a) 4
b) 2
c) 4
d) 1 (implied)
e) 1 (implied)
Next, we need to determine the stoichiometric coefficients for oxygen (O2). We can do this by comparing the coefficients to the coefficient of ammonia (NH3).
From the balanced equations, we see that the coefficient for oxygen (O2) is:
a) 5
b) 5
c) 5
d) 5/4
e) 5
Given that the reaction involves 1.000 mole of ammonia and the coefficients for ammonia are 4 in options (a), (c), and (e), we can eliminate options (b) and (d) since the stoichiometric coefficient for ammonia is not equal to 1.
Next, we can check whether the options that have a coefficient of 4 for ammonia also satisfy the stoichiometry for oxygen. The stoichiometric coefficient for oxygen should be equal to 5.
From the remaining options (a), (c), and (e), we can see that option (e) satisfies the stoichiometry for oxygen, as the coefficient is 5, while options (a) and (c) do not meet this requirement. Therefore, the balanced chemical equation that best fits the given information is:
e) NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) △H = + 240 kJ
Therefore, the correct option is e) NH3(g) + 5O2(g) –960 kJ → 4NO(g) + 6H2O(g) with a ΔH of +240 kJ.