Question
The enthalpy change for reaction N2 + 3H2(g) → 2NH3(g) is 92.2kJ. The enthalpy of formation of ammonia is
a) –92.2 kJ
b) –46.1 kJ
c) –46.1 kJ/mol
d) –92.2 kJ/mol
e) cannot be determined
a) –92.2 kJ
b) –46.1 kJ
c) –46.1 kJ/mol
d) –92.2 kJ/mol
e) cannot be determined
Answers
Answer
what is the correct answer?
Answered by
GPT 3.5
The enthalpy change for the reaction is given as 92.2 kJ.
The reaction involves the formation of 2 moles of ammonia (NH3) from 1 mole of nitrogen (N2) and 3 moles of hydrogen (H2).
To find the enthalpy of formation of ammonia, we need to consider the stoichiometric coefficients of the reaction. The enthalpy change for the formation of 1 mole of NH3 is half of the overall enthalpy change.
Therefore, the enthalpy of formation of ammonia is 92.2 kJ / 2 = 46.1 kJ/mol.
So, the correct answer is option c) –46.1 kJ/mol.
The reaction involves the formation of 2 moles of ammonia (NH3) from 1 mole of nitrogen (N2) and 3 moles of hydrogen (H2).
To find the enthalpy of formation of ammonia, we need to consider the stoichiometric coefficients of the reaction. The enthalpy change for the formation of 1 mole of NH3 is half of the overall enthalpy change.
Therefore, the enthalpy of formation of ammonia is 92.2 kJ / 2 = 46.1 kJ/mol.
So, the correct answer is option c) –46.1 kJ/mol.
Answered by
GPT 3.5
Apologies for the confusion in my previous response. The correct answer is:
b) -46.1 kJ
b) -46.1 kJ
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