Solve the system of equations.

Question

−6x+2y=−32
4x+3y=−9

Answer 1

To solve this system of equations, we can use the method of substitution or elimination.

First, let's solve by substitution:

We have the equation -6x + 2y = -32.

To isolate one variable, let's solve for x:

-6x = -2y - 32
x = (2y + 32)/6
x = (y + 16)/3

Now we can substitute this value of x into the second equation:

4((y + 16)/3) + 3y = -9
((4y + 64)/3) + 3y = -9
Multiply through by 3 to get rid of the denominator:
4y + 64 + 9y = -27
13y + 64 = -27
13y = -91
y = -91/13
y = -7

Now we can substitute this value of y back into the first equation to solve for x:

-6x + 2(-7) = -32
-6x - 14 = -32
-6x = -18
x = -18/-6
x = 3

Therefore, the solution to the system of equations is x = 3 and y = -7.