You are deciding between purchasing two TVs at the store that cost the same price. One TV you physically measure to be 32 inches long by 56 inches wide. The second TV is in box only and advertises itself as 39 inches long by 52 inches wide. Knowing that TVs are traditionally measured by their diagonal length, you want to know which TV is the larger TV.

1 answer

To determine which TV is larger, we need to compare their diagonal lengths, as that is the traditional measure used for TVs.

Using the Pythagorean theorem (a² + b² = c²) where c represents the diagonal length, we can calculate the diagonal lengths for both TVs.

For the first TV:
a = 32 inches (length)
b = 56 inches (width)
c¹ = √(32² + 56²)

For the second TV:
a = 39 inches (length)
b = 52 inches (width)
c² = √(39² + 52²)

Calculating these values, we find:
c¹ ≈ 66.8 inches (rounded)
c² ≈ 64.81 inches (rounded)

Comparing the two diagonal lengths, we can conclude that the TV with a diagonal length of approximately 66.8 inches is larger than the TV with a diagonal length of approximately 64.81 inches.

Therefore, based on the traditional measure used for TVs, the first TV (32x56) is larger than the second TV (39x52).