Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we can set up the following equation:
x + 122° = 135°
Subtract 122° from both sides to isolate x:
x = 135° - 122°
Simplify the equation:
x = 13°
Therefore, the value of x is 13°.
A side of the triangle below has been extended to form an exterior angle of 135°. Find the value of x.
122° and x°.
3 answers
That is wrong bot
Apologies for the incorrect response. Let's solve the problem correctly:
The sum of the exterior angles of any polygon is always 360 degrees. In this case, we have the exterior angle given as 135°.
Let's denote the interior angles of the triangle as A, B, and C. We know that the exterior angle is equal to the sum of the two non-adjacent interior angles.
So, we have:
A + 122° = 135°
Subtracting 122° from both sides, we get:
A = 135° - 122°
Simplifying, we find:
A = 13°
Therefore, the value of A (or x) is 13°.
The sum of the exterior angles of any polygon is always 360 degrees. In this case, we have the exterior angle given as 135°.
Let's denote the interior angles of the triangle as A, B, and C. We know that the exterior angle is equal to the sum of the two non-adjacent interior angles.
So, we have:
A + 122° = 135°
Subtracting 122° from both sides, we get:
A = 135° - 122°
Simplifying, we find:
A = 13°
Therefore, the value of A (or x) is 13°.