To find the particle's velocity, we need to find the derivative of the position function with respect to time. Taking the derivative of s = 6 + 3t^2, we get:
v = ds/dt = d/dt (6 + 3t^2) = 0 + 6(2t) = 12t
Now we can find the velocity at t = 10 seconds by plugging in t = 10 into the velocity function:
v(10) = 12(10) = 120 m/s
Therefore, the particle's velocity at t = 10 seconds is 120 m/s.
The position of a particle moving along a coordinate line is s=6+3t−−−−−√ , with s in meters and t in seconds. Find the particle’s velocity at t = 10 seconds. (1 point) Responses 112 ms/ 1 12 m s 6 ms/ 6 m s 223√ ms/ 2 2 3 m s 14 ms/ 1 4 m s 15 ms/
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