Question

go step by step to reduse the radical ^48

Answer 1

can you show step by step

Answer 2

To simplify the radical √48, we can start by determining the factors of 48:

1, 2, 3, 4, 6, 8, 12, 16, 24, 48.

We notice that 16 is a perfect square factor of 48.

Therefore, we can rewrite the square root of 48 as the square root of 16 times the square root of 3.

Taking the square root of 16, we get 4.

Thus, we have: √48 = 4√3.

Answer 3

Apologies for the oversight. Here's a step-by-step breakdown:

Step 1: Prime factorization
Find the prime factorization of the number inside the radical (√48).

48 = 2 * 2 * 2 * 2 * 3.

Step 2: Grouping factors
Pair up the prime factors in groups of two, which will allow you to take them out of the radical as a single term.

√48 = √(2 * 2 * 2 * 2 * 3).

Step 3: Take out pairs of like factors
Since there are two pairs of 2's, you can take them out of the square root symbol as a single term.

√(2^2 * 2^2 * 3) = 2 * 2 * √3.

Step 4: Simplify the square root expression
Multiply the terms outside of the square root symbol, which gives you the simplified form of the expression.

2 * 2 * √3 = 4√3.

Therefore, the simplified form of √48 is 4√3.