Question
If a Ford weighs 1500kg and is traveling at a speed of 21m/s, what is the K.E if the speed of the Ford is doubled?
Answers
GPT 3.5
To find the kinetic energy of the Ford when its speed is doubled, we need to use the formula for kinetic energy:
K.E = (1/2) * m * v^2
Where:
K.E = Kinetic energy
m = Mass of the Ford
v = Velocity of the Ford
Given that the Ford weighs 1500 kg and is traveling at a speed of 21 m/s, we can substitute these values into the formula to find the initial kinetic energy:
K.E = (1/2) * 1500 kg * (21 m/s)^2
K.E = (1/2) * 1500 kg * 441 m^2/s^2
K.E = 154,350 kg m^2/s^2 (or Joules)
To find the kinetic energy when the speed is doubled, we need to find the new velocity. If the speed is doubled, it becomes 21 m/s * 2 = 42 m/s.
Substituting the new velocity into the formula:
K.E = (1/2) * 1500 kg * (42 m/s)^2
K.E = (1/2) * 1500 kg * 1764 m^2/s^2
K.E = 1,323,000 kg m^2/s^2 (or Joules)
Therefore, when the speed of the Ford is doubled, the kinetic energy increases to 1,323,000 Joules.
K.E = (1/2) * m * v^2
Where:
K.E = Kinetic energy
m = Mass of the Ford
v = Velocity of the Ford
Given that the Ford weighs 1500 kg and is traveling at a speed of 21 m/s, we can substitute these values into the formula to find the initial kinetic energy:
K.E = (1/2) * 1500 kg * (21 m/s)^2
K.E = (1/2) * 1500 kg * 441 m^2/s^2
K.E = 154,350 kg m^2/s^2 (or Joules)
To find the kinetic energy when the speed is doubled, we need to find the new velocity. If the speed is doubled, it becomes 21 m/s * 2 = 42 m/s.
Substituting the new velocity into the formula:
K.E = (1/2) * 1500 kg * (42 m/s)^2
K.E = (1/2) * 1500 kg * 1764 m^2/s^2
K.E = 1,323,000 kg m^2/s^2 (or Joules)
Therefore, when the speed of the Ford is doubled, the kinetic energy increases to 1,323,000 Joules.