Question
what happens if a vehicle is traveling at 21m/s and has a k.e of 300,750 and the speed is doubled?
Answers
GPT 3.5
If a vehicle is initially traveling at 21 m/s with a kinetic energy of 300,750, and its speed is doubled, we can calculate the new kinetic energy using the formula:
Kinetic energy = (1/2) * mass * (velocity)^2
Let's assume the mass of the vehicle remains constant throughout.
Initial kinetic energy = (1/2) * mass * (initial velocity)^2
300,750 = (1/2) * mass * (21)^2
Now, we need to calculate the new kinetic energy:
Final velocity = 2 * initial velocity
Final velocity = 2 * 21 m/s
Final velocity = 42 m/s
New kinetic energy = (1/2) * mass * (final velocity)^2
New kinetic energy = (1/2) * mass * (42)^2
Comparing the two equations:
300,750 = (1/2) * mass * (21)^2
New kinetic energy = (1/2) * mass * (42)^2
We can see that the new kinetic energy will be four times the initial kinetic energy:
New kinetic energy = 4 * 300,750
New kinetic energy = 1,203,000
Therefore, if the speed of the vehicle is doubled, the new kinetic energy will be 1,203,000.
Kinetic energy = (1/2) * mass * (velocity)^2
Let's assume the mass of the vehicle remains constant throughout.
Initial kinetic energy = (1/2) * mass * (initial velocity)^2
300,750 = (1/2) * mass * (21)^2
Now, we need to calculate the new kinetic energy:
Final velocity = 2 * initial velocity
Final velocity = 2 * 21 m/s
Final velocity = 42 m/s
New kinetic energy = (1/2) * mass * (final velocity)^2
New kinetic energy = (1/2) * mass * (42)^2
Comparing the two equations:
300,750 = (1/2) * mass * (21)^2
New kinetic energy = (1/2) * mass * (42)^2
We can see that the new kinetic energy will be four times the initial kinetic energy:
New kinetic energy = 4 * 300,750
New kinetic energy = 1,203,000
Therefore, if the speed of the vehicle is doubled, the new kinetic energy will be 1,203,000.