22 students completed 80 puzzles. How many puzzles would 1 student complete? (round to tenth)

3 answers

To find out how many puzzles one student would complete, you can divide the total number of puzzles by the number of students:

\[ \text{Puzzles per student} = \frac{\text{Total puzzles}}{\text{Number of students}} = \frac{80}{22} \]

Calculating that gives:

\[ \frac{80}{22} \approx 3.636363636 \]

Rounding to the tenth, one student would complete approximately:

\[ \text{Puzzles per student} \approx 3.6 \]

So, one student would complete about 3.6 puzzles.

step by step 80 / 20

Sure! Let's go step by step to divide \( 80 \) by \( 22 \).

  1. Set Up the Division: We want to divide \( 80 \) by \( 22 \). This can be expressed as:

    \[ 80 \div 22 \]

  2. Perform the Division: Start by seeing how many times \( 22 \) can fit into \( 80 \).

    • Estimate:
      • \( 22 \times 1 = 22 \)
      • \( 22 \times 2 = 44 \)
      • \( 22 \times 3 = 66 \)
      • \( 22 \times 4 = 88 \) (too much)

    So, \( 22 \) can fit into \( 80 \) three times.

  3. Multiply: Now we multiply \( 22 \) by \( 3 \):

    \[ 22 \times 3 = 66 \]

  4. Subtract: Now subtract \( 66 \) from \( 80 \):

    \[ 80 - 66 = 14 \]

  5. Write the Remainder: Now we have a remainder of \( 14 \).

  6. Add a Decimal: Since \( 80 \) is greater than \( 22 \), we can continue dividing by adding a decimal point and a zero to the \( 14 \) to make it \( 140 \):

    \[ 80.0 \div 22 = 3.0 \]

  7. Continue Division: Now determine how many times \( 22 \) fits into \( 140 \):

    • \( 22 \times 6 = 132 \)
    • \( 22 \times 7 = 154 \) (too much)

    So, \( 22 \) fits \( 6 \) times.

  8. Multiply Again: Multiply \( 22 \) by \( 6 \):

    \[ 22 \times 6 = 132 \]

  9. Subtract Again: Now subtract \( 132 \) from \( 140 \):

    \[ 140 - 132 = 8 \]

  10. Add Another Decimal: Add to the division result:

    \[ 80.00 \div 22 \approx 3.6 \]

  11. Repeat for More Precision: Add another \( 0 \) to \( 8 \) to make \( 80 \) and continue dividing:

    • \( 22 \) fits \( 3 \) times into \( 80 \) (because \( 22 \times 3 = 66 \)).
    • Subtract \( 66 \) from \( 80 \):

    \[ 80 - 66 = 14 \]

  12. Final Result: The result we derived from dividing \( 80 \) by \( 22 \) gives us:

\[ 80 \div 22 \approx 3.636363636... \]

When rounded to the nearest tenth, it is \( 3.6 \).

So, the final answer is that one student would complete approximately 3.6 puzzles.