3 answers
To find out how many puzzles one student would complete, you can divide the total number of puzzles by the number of students:
\[ \text{Puzzles per student} = \frac{\text{Total puzzles}}{\text{Number of students}} = \frac{80}{22} \]
Calculating that gives:
\[ \frac{80}{22} \approx 3.636363636 \]
Rounding to the tenth, one student would complete approximately:
\[ \text{Puzzles per student} \approx 3.6 \]
So, one student would complete about 3.6 puzzles.
Sure! Let's go step by step to divide \( 80 \) by \( 22 \).
Set Up the Division: We want to divide \( 80 \) by \( 22 \). This can be expressed as:
\[ 80 \div 22 \]
Perform the Division: Start by seeing how many times \( 22 \) can fit into \( 80 \).
So, \( 22 \) can fit into \( 80 \) three times.
Multiply: Now we multiply \( 22 \) by \( 3 \):
\[ 22 \times 3 = 66 \]
Subtract: Now subtract \( 66 \) from \( 80 \):
\[ 80 - 66 = 14 \]
Write the Remainder: Now we have a remainder of \( 14 \).
Add a Decimal: Since \( 80 \) is greater than \( 22 \), we can continue dividing by adding a decimal point and a zero to the \( 14 \) to make it \( 140 \):
\[ 80.0 \div 22 = 3.0 \]
Continue Division: Now determine how many times \( 22 \) fits into \( 140 \):
So, \( 22 \) fits \( 6 \) times.
Multiply Again: Multiply \( 22 \) by \( 6 \):
\[ 22 \times 6 = 132 \]
Subtract Again: Now subtract \( 132 \) from \( 140 \):
\[ 140 - 132 = 8 \]
Add Another Decimal: Add to the division result:
\[ 80.00 \div 22 \approx 3.6 \]
Repeat for More Precision: Add another \( 0 \) to \( 8 \) to make \( 80 \) and continue dividing:
\[ 80 - 66 = 14 \]
Final Result: The result we derived from dividing \( 80 \) by \( 22 \) gives us:
\[ 80 \div 22 \approx 3.636363636... \]
When rounded to the nearest tenth, it is \( 3.6 \).
So, the final answer is that one student would complete approximately 3.6 puzzles.
