22.57% sulfur, 45.06% oxygen and the remaining element as sodium. What is the total number of moles of sodium that is present in the salt if the salt product weighs 5.831g?

1 answer

First, we need to calculate the molar mass of the salt.

The molar mass of sulfur (S) is 32.06 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.
The molar mass of sodium (Na) is 22.99 g/mol.

So, the molar mass of the salt = (0.2257*32.06) + (0.4506*16.00) + (0.3237*22.99) = 19.78 + 7.21 + 7.46 = 34.45 g/mol

Next, we need to find the number of moles of the salt in 5.831g.

Number of moles = Mass / Molar mass
Number of moles = 5.831g / 34.45 g/mol = 0.1691 mol

As 0.2257 moles of the salt contains 1 mole of sodium, we can calculate the number of moles of sodium in 0.1691 moles of the salt.

Number of moles of sodium = 0.1691 mol * (1 mol Na / 0.2257 mol salt) = 0.7488 mol

Therefore, the total number of moles of sodium in 5.831g of the salt is 0.7488 mol.