One-quater of the sum of two consecutive odd numbers is 14.find the old numbers

Answer 1

Let's represent the two consecutive odd numbers as (2n-1) and (2n+1), where n is an integer.

The sum of these two numbers is:
(2n-1) + (2n+1) = 4n

Now, let's find one-quarter of this sum:
(1/4)(4n) = n

According to the problem, n is equal to 14.

So, the two consecutive odd numbers are:
(2*14-1) = 27 and (2*14+1) = 29.

Therefore, the odd numbers are 27 and 29.