2. Rewrite ∛40 as a product of an integer and another irrational cube root

3. Find area of circle with diameter of 10.2 cm (round to tenth and put units)
4. Find circumference of circle with radius of 2.7 cm (round to tenth and put units)
5. Rewrite √45 in as a product of an integer and irrational square root.
(do simple work)

1 answer

2. ∛40 = ∛(8×5)=2∛5

3. The diameter of the circle is 10.2 cm, so the radius is half of that, which is 5.1 cm. The formula for the area of a circle is A = πr², substituting the values we have:

A = π(5.1)² = 25.91 cm² (rounded to tenth)

4. The radius of the circle is 2.7 cm. The formula for the circumference of a circle is C = 2πr, substituting the value we have:

C = 2π(2.7) = 16.96 cm (rounded to tenth)

5. √45 can be written as √(9×5) = 3√5