To simplify the expression, let's break it down step by step:
Step 1: Calculate the product of 33 and 10.
33 x 10 = 330
Step 2: Simplify the square root of 28.
The square root of 28 can be simplified by factoring out the perfect square. Since 4 is a perfect square that can be found in 28, we can write:
√28 = √(4 x 7)
Next, we can take the square root of 4:
√(4 x 7) = 2√7
Step 3: Final expression
The final expression in simplest radical form is:
330√7
What is the product of 33 and 10, square root of, 28, end square root10
28
in simplest radical form?
3 answers
give me the simplest form there is
I apologize for the previous incorrect response. Let's simplify the expression correctly:
To find the product of 33 and (square root of 28 + square root of 10), we can follow these steps:
Step 1: Simplify the square root of 28 and 10:
The square root of 28 can be simplified as 2√7.
The square root of 10 remains as √10.
Step 2: Substitute the simplified values into the expression:
33 * (2√7 + √10)
Step 3: Distribute the multiplication:
(33 * 2√7) + (33 * √10)
This gives us:
66√7 + 33√10
So, the simplest form of the expression is:
66√7 + 33√10.
To find the product of 33 and (square root of 28 + square root of 10), we can follow these steps:
Step 1: Simplify the square root of 28 and 10:
The square root of 28 can be simplified as 2√7.
The square root of 10 remains as √10.
Step 2: Substitute the simplified values into the expression:
33 * (2√7 + √10)
Step 3: Distribute the multiplication:
(33 * 2√7) + (33 * √10)
This gives us:
66√7 + 33√10
So, the simplest form of the expression is:
66√7 + 33√10.