Question

What is the product of 33 and 10, square root of, 28, end square root10
28
​
in simplest radical form?

Answer 1

give me the simplest form there is

Answer 2

To simplify the expression, let's break it down step by step:

Step 1: Calculate the product of 33 and 10.

33 x 10 = 330

Step 2: Simplify the square root of 28.

The square root of 28 can be simplified by factoring out the perfect square. Since 4 is a perfect square that can be found in 28, we can write:

√28 = √(4 x 7)

Next, we can take the square root of 4:

√(4 x 7) = 2√7

Step 3: Final expression

The final expression in simplest radical form is:

330√7

Answer 3

I apologize for the previous incorrect response. Let's simplify the expression correctly:

To find the product of 33 and (square root of 28 + square root of 10), we can follow these steps:

Step 1: Simplify the square root of 28 and 10:
The square root of 28 can be simplified as 2√7.
The square root of 10 remains as √10.

Step 2: Substitute the simplified values into the expression:
33 * (2√7 + √10)

Step 3: Distribute the multiplication:
(33 * 2√7) + (33 * √10)

This gives us:
66√7 + 33√10

So, the simplest form of the expression is:
66√7 + 33√10.