What is the product of 33 and 10, square root of, 40, end square root10

40

in simplest radical form?

5 answers

The product of 33 and the square root of 40 is:

33 * √40

To simplify the radical form, we need to factorize the number inside the square root:

√(4 * 10)

We can then take out any perfect square factor from under the square root:

2√10

Therefore, the product of 33 and the square root of 40 in simplest radical form is 2√10.
Express in simplest radical form.
start fraction, square root of, 1134, end square root, divided by, square root of, 7, end square root, end fraction
7


1134


To express the fraction √1134 / √7 in simplest radical form, we can simplify the square root terms individually and then divide:

Step 1: Simplify the square roots:
√1134 = √(2 * 3^2 * 7^2) = 3 * 7√2 = 21√2
√7 = √(7) = √7

Step 2: Divide the square root terms:
(21√2) / (√7)

Step 3: Rationalize the denominator by multiplying both the numerator and the denominator by √7:
(21√2 * √7) / (√7 * √7) = (21√14) / 7

Step 4: Simplify the expression:
21√14 / 7 = 3√14

Therefore, the expression √1134 / √7 simplified in simplest radical form is 3√14.
pls try again
I apologize for the previous response. Let's simplify the fraction √1134 / √7 in simplest radical form:

Step 1: Simplify the square roots:
√1134 = √(2 * 3^2 * 7^2) = 3 * 7√2 = 21√2
√7 = √(7)

Step 2: Divide the square root terms:
(21√2) / (√7)

Step 3: Rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of the denominator (√7):
((21√2) / (√7)) * (√7 / √7) = (21√2 * √7) / 7

Step 4: Simplify the expression:
(21√14) / 7 = 3√14

Therefore, the expression √1134 / √7 simplified in simplest radical form is 3√14.