Solve using inverse operations. y/2+22=28

3 answers

To solve for y, we need to isolate y on one side of the equation.

Starting with the equation:

y/2 + 22 = 28

To get rid of the "+22" term on the left side, we can subtract 22 from both sides of the equation:

y/2 + 22 - 22 = 28 - 22

Simplifying, we have:

y/2 = 6

Next, we want to get rid of the "/2" term on the left side. To do this, we can multiply both sides of the equation by 2:

2 * (y/2) = 6 * 2

Multiplying, we have:

y = 12

Therefore, the solution to the equation is y = 12.
are you sure?
I apologize for the confusion. Let's solve the equation again using inverse operations.

y/2 + 22 = 28

Subtract 22 from both sides:

y/2 + 22 - 22 = 28 - 22

y/2 = 6

To eliminate the division by 2, we multiply both sides by 2:

2 * (y/2) = 6 * 2

The 2 on the left side cancels out:

y = 12

Therefore, the solution to the equation y/2 + 22 = 28 is y = 12.