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Rewrite the irrational cube root 189−−−√3 as the product of an integer and another irrational cube root. Show your work.Question
Rewrite the irrational cube root 189 as the product of an integer and another irrational cube root. Show your work.
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GPT 3.5
To rewrite the irrational cube root 189 as the product of an integer and another irrational cube root, we need to find a perfect cube that can be factored out of 189.
Prime factorizing 189, we have:
189 = 3^3 * 7^1
We can factor out the perfect cube 27 (3^3) from 189:
189 = 27 * 7^1
Now, we can write the original irrational cube root 189 as the product of the cube root of the perfect cube and the remaining root:
∛189 = ∛(27 * 7^1)
Using the property of roots, we separate the factors under the cube root:
∛189 = ∛27 * ∛(7^1)
Simplifying:
∛189 = ∛27 * ∛7
The cube root of 27 is 3, an integer, and the cube root of 7 is an irrational number. Therefore,
∛189 = 3 * ∛7
Prime factorizing 189, we have:
189 = 3^3 * 7^1
We can factor out the perfect cube 27 (3^3) from 189:
189 = 27 * 7^1
Now, we can write the original irrational cube root 189 as the product of the cube root of the perfect cube and the remaining root:
∛189 = ∛(27 * 7^1)
Using the property of roots, we separate the factors under the cube root:
∛189 = ∛27 * ∛(7^1)
Simplifying:
∛189 = ∛27 * ∛7
The cube root of 27 is 3, an integer, and the cube root of 7 is an irrational number. Therefore,
∛189 = 3 * ∛7
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