5√10 + √10 = (5 + 1)√10 = 6√10
So, the answer is option A. 6√10.
add 5√10 + √10
A. 6√10
B. 6√20
C. √60
D. √25
15 answers
subtract 11√19 - 5√19
The difference is ___
The difference is ___
To subtract 11√19 - 5√19, we can combine like terms.
11√19 - 5√19 = (11 - 5)√19
The difference is 6√19.
11√19 - 5√19 = (11 - 5)√19
The difference is 6√19.
Multiply (5√19) (6√2). give an exact answer
To multiply (5√19) (6√2), we can use the commutative property to rearrange the terms:
(5√19) (6√2) = 5 * 6 * √19 * √2
Multiplying the coefficients gives:
(5√19) (6√2) = 30 * √19 * √2
Now, using the property √a * √b = √(a * b), we can combine the radicals:
30 * √19 * √2 = 30 * √(19 * 2)
Simplifying further:
30 * √(19 * 2) = 30 * √38
Therefore, the exact answer is 30√38.
(5√19) (6√2) = 5 * 6 * √19 * √2
Multiplying the coefficients gives:
(5√19) (6√2) = 30 * √19 * √2
Now, using the property √a * √b = √(a * b), we can combine the radicals:
30 * √19 * √2 = 30 * √(19 * 2)
Simplifying further:
30 * √(19 * 2) = 30 * √38
Therefore, the exact answer is 30√38.
Divide √95 / 3√5 give an exact answer
To divide √95 / 3√5, we can rationalize the denominator by multiplying both the numerator and denominator by the conjugate of the denominator.
√95 / 3√5 = (√95 / 3√5) * (√5 / √5)
Multiplying the numerators and denominators gives us:
(√95 * √5) / (3√5 * √5)
Simplifying the numerator and denominator:
√475 / (3 * 5)
√475 / 15
Therefore, the exact answer is (√475) / 15.
√95 / 3√5 = (√95 / 3√5) * (√5 / √5)
Multiplying the numerators and denominators gives us:
(√95 * √5) / (3√5 * √5)
Simplifying the numerator and denominator:
√475 / (3 * 5)
√475 / 15
Therefore, the exact answer is (√475) / 15.
Divide 36√39 / 9√13 give an exact awnser
To divide 36√39 / 9√13, we can simplify the expression by canceling out common factors.
First, let's simplify the denominators:
36√39 = (√36 * √39) = 6√39
9√13 = (√9 * √13) = 3√13
Now we can rewrite the expression:
36√39 / 9√13 = (6√39) / (3√13)
Next, let's divide the coefficients:
(6√39) / (3√13) = 6/3 * (√39 / √13) = 2 * (√39 / √13)
Since the square root of 39 cannot be further simplified, the exact answer is:
2 * (√39 / √13) = 2√39 / √13
Thus, the exact answer is 2√39 / √13.
First, let's simplify the denominators:
36√39 = (√36 * √39) = 6√39
9√13 = (√9 * √13) = 3√13
Now we can rewrite the expression:
36√39 / 9√13 = (6√39) / (3√13)
Next, let's divide the coefficients:
(6√39) / (3√13) = 6/3 * (√39 / √13) = 2 * (√39 / √13)
Since the square root of 39 cannot be further simplified, the exact answer is:
2 * (√39 / √13) = 2√39 / √13
Thus, the exact answer is 2√39 / √13.
simplify √48
To simplify √48, we can factor 48 into its prime factors.
48 can be factored as 2 * 2 * 2 * 2 * 3.
Taking pairs of factors out, we have:
√48 = √(2 * 2 * 2 * 2 * 3)
= 2 * 2 * √(2 * 3)
= 4√(2 * 3)
= 4√6
Therefore, the simplified form of √48 is 4√6.
48 can be factored as 2 * 2 * 2 * 2 * 3.
Taking pairs of factors out, we have:
√48 = √(2 * 2 * 2 * 2 * 3)
= 2 * 2 * √(2 * 3)
= 4√(2 * 3)
= 4√6
Therefore, the simplified form of √48 is 4√6.
what is the irrational square root √63 rewritten as the product of an integer and another irrational square root in simplest form
To rewrite the irrational square root √63 as the product of an integer and another irrational square root in simplest form, we need to find the largest perfect square that divides 63.
63 can be factored as 7 * 9, and 9 is a perfect square (3 * 3).
Therefore, we can rewrite √63 as:
√63 = √(7 * 9) = √7 * √9 = √7 * 3
So, the simplest form of √63 as the product of an integer and another irrational square root is 3√7.
63 can be factored as 7 * 9, and 9 is a perfect square (3 * 3).
Therefore, we can rewrite √63 as:
√63 = √(7 * 9) = √7 * √9 = √7 * 3
So, the simplest form of √63 as the product of an integer and another irrational square root is 3√7.
what is the irrational cube root 3√81 rewritten as a product of an integer and another irrational cube root
To rewrite the irrational cube root 3√81 as a product of an integer and another irrational cube root, we need to find the largest perfect cube that divides 81.
81 can be factored as 3 * 3 * 3 * 3, and 3 is a perfect cube (3 * 3 * 3).
Therefore, we can rewrite 3√81 as:
3√81 = 3√(3 * 3 * 3 * 3) = 3 * 3√3 = 9√3
So, the rewrite of 3√81 as a product of an integer and another irrational cube root is 9√3.
81 can be factored as 3 * 3 * 3 * 3, and 3 is a perfect cube (3 * 3 * 3).
Therefore, we can rewrite 3√81 as:
3√81 = 3√(3 * 3 * 3 * 3) = 3 * 3√3 = 9√3
So, the rewrite of 3√81 as a product of an integer and another irrational cube root is 9√3.