Write an equation in POINT SLOPE FORM of a line through point J(3,-2) with a slope of -5.

Answer 1

The point-slope form of a linear equation is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Given that the point is J(3,-2) and the slope is -5, we can substitute these values into the point-slope form equation:

y - (-2) = -5(x - 3)

Simplifying:

y + 2 = -5x + 15

Subtracting 2 from both sides:

y = -5x + 13

So, the equation in point-slope form of the line through point J(3,-2) with a slope of -5 is y = -5x + 13.