The equation for a point on the unit circle is given by x^2 + y^2 = 1. Since the x-coordinate is 2 and the radius is -1, we can substitute these values into the equation:
(2)^2 + y^2 = 1
4 + y^2 = 1
y^2 = -3
Since the square of any real number cannot be negative, there are no real solutions for y.
A point (2, y) lies on the unit circle such that r=-1. What is the y-coordinate for this point?
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