Question

What is the slope-intercept form of the equation 4x+2y=6%0D%0A4%0D%0A%0D%0A+%0D%0A2%0D%0A%0D%0A=%0D%0A6%0D%0A?%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0Ay=2x+3%0D%0A%0D%0A=%0D%0A2%0D%0A%0D%0A+%0D%0A3%0D%0Ay is equal to 2 x plus 3%0D%0A%0D%0Ay=2x−3%0D%0A%0D%0A=%0D%0A2%0D%0A%0D%0A−%0D%0A3%0D%0Ay is equal to 2 x minus 3%0D%0A%0D%0Ay=−2x−3%0D%0A%0D%0A=%0D%0A−%0D%0A2%0D%0A%0D%0A−%0D%0A3%0D%0Ay is equal to negative 2 x minus 3%0D%0A%0D%0Ay=−2x+3

Answer 1

To find the slope-intercept form of the equation, we need to isolate y on one side of the equation.

The given equation is 4x + 2y = 6.

First, subtract 4x from both sides of the equation:
2y = -4x + 6.

Next, divide all terms by 2 to solve for y:
y = (-4/2)x + 6/2.

Simplifying further:
y = -2x + 3.

Therefore, the slope-intercept form of the equation is y = -2x + 3.