Question
A student drop the same 10 kg ball from hearts of 12 and 3 m which paragraph accurately shows the boss kinetic energy when dropped from each height
Answers
Answered by
GPT 3.5
When the student drops the 10 kg ball from a height of 12 m, the ball's kinetic energy can be calculated using the formula: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the ball (10 kg), and v is the velocity of the ball when it hits the ground.
Given that the ball is dropped (not thrown), we can assume that its initial velocity is 0 m/s. Using the equation, the kinetic energy at this height is:
KE = 0.5 * 10 kg * (0 m/s)^2 = 0 Joules
On the other hand, when the same 10 kg ball is dropped from a height of 3 m, the ball's kinetic energy can again be calculated using the same formula:
KE = 0.5 * 10 kg * v^2
Since the ball is being dropped, we can calculate its final velocity using the equation: v = sqrt(2 * g * h), where g is the acceleration due to gravity (approximately 9.8 m/s^2) and h is the height (3 m). Plugging these values into the equation, we get:
v = sqrt(2 * 9.8 m/s^2 * 3 m) ≈ 7.67 m/s
Substituting this into the kinetic energy formula:
KE = 0.5 * 10 kg * (7.67 m/s)^2 ≈ 294.9 Joules
Therefore, the ball's kinetic energy when dropped from a height of 12 m is 0 Joules, but when dropped from a height of 3 m, it is approximately 294.9 Joules.
Given that the ball is dropped (not thrown), we can assume that its initial velocity is 0 m/s. Using the equation, the kinetic energy at this height is:
KE = 0.5 * 10 kg * (0 m/s)^2 = 0 Joules
On the other hand, when the same 10 kg ball is dropped from a height of 3 m, the ball's kinetic energy can again be calculated using the same formula:
KE = 0.5 * 10 kg * v^2
Since the ball is being dropped, we can calculate its final velocity using the equation: v = sqrt(2 * g * h), where g is the acceleration due to gravity (approximately 9.8 m/s^2) and h is the height (3 m). Plugging these values into the equation, we get:
v = sqrt(2 * 9.8 m/s^2 * 3 m) ≈ 7.67 m/s
Substituting this into the kinetic energy formula:
KE = 0.5 * 10 kg * (7.67 m/s)^2 ≈ 294.9 Joules
Therefore, the ball's kinetic energy when dropped from a height of 12 m is 0 Joules, but when dropped from a height of 3 m, it is approximately 294.9 Joules.