Asked by Gweedo8
A student prepares phosphorous acid by reacting solid phosphorous triodide with water
PI3+H2O-->H3PO3+HI
The student needs to obtain 0.250L of phosphorous acid. (d=1.651g/mL). The procedure calls for a 45.0% excess of water and a yield of 75.0%. How much phosphorous triiodide should be weighed out?
My brain is fried from math today can someone help with the steps to solve this???
PI3+H2O-->H3PO3+HI
The student needs to obtain 0.250L of phosphorous acid. (d=1.651g/mL). The procedure calls for a 45.0% excess of water and a yield of 75.0%. How much phosphorous triiodide should be weighed out?
My brain is fried from math today can someone help with the steps to solve this???