If a right triangle has a leg with length 12 and the hypotenuse is 16, how long is the other leg? Round to the nearest tenth, if necessary.(1 point)

Question

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Answer 1

Let the length of the other leg be $x$. According to the Pythagorean theorem, we have
\[x^2 + 12^2 = 16^2\]
\[x^2 + 144 = 256\]
\[x^2 = 112\]
\[x = \sqrt{112} \approx \boxed{10.6}\]