2t+8≥−4(t+1)

Answer 1

2t + 8 ≥ -4(t + 1)

Let's solve for t step by step:

First, distribute -4 to t + 1:
2t + 8 ≥ -4t - 4

Next, combine like terms on both sides of the equation:
2t + 4t + 8 ≥ -4

Simplify:
6t + 8 ≥ -4

Now, subtract 8 from both sides of the equation:
6t ≥ -12

Finally, divide both sides by 6 to solve for t:
t ≥ -2

Therefore, the solution to the inequality 2t + 8 ≥ -4(t + 1) is t ≥ -2.