To rewrite ^3√81 as a product of an integer and another irrational cube root, we can factor 81 into its prime factors. Since 81 is equal to 3 * 3 * 3 * 3 (or 3^4), we can rewrite ^3√81 as ^3√(3^4).
We can rewrite this as the product ^3√3 * ^3√(3^3).
Therefore, the irrational cube root ^3√81 can be rewritten as the product 3 * ^3√3.
What is the irrational cube root ^3√81 rewritten as a product of an integer and another irrational cube root?
3 answers
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To rewrite the irrational cube root ^3√81 as a product of an integer and another irrational cube root, we need to find a perfect cube that divides 81.
The perfect cube that divides 81 is 27 since 27 * 3 = 81.
Therefore, we can rewrite ^3√81 as:
^3√81 = ^3√(27 * 3)
To further simplify, we can rewrite it as:
^3√81 = ^3√27 * ^3√3
So, the irrational cube root ^3√81 can be rewritten as the product of ∛27 and ∛3.
To rewrite the irrational cube root ^3√81 as a product of an integer and another irrational cube root, we need to find a perfect cube that divides 81.
The perfect cube that divides 81 is 27 since 27 * 3 = 81.
Therefore, we can rewrite ^3√81 as:
^3√81 = ^3√(27 * 3)
To further simplify, we can rewrite it as:
^3√81 = ^3√27 * ^3√3
So, the irrational cube root ^3√81 can be rewritten as the product of ∛27 and ∛3.
1 answer