Question

Using the quadratic formula, find the solution to 3x2 + 18x + 24 = 0.
(1 point)
• х = -4
02＝－2
02=4,2=2
• х = —2, х = —4

Answer 1

To find the solutions of the equation 3x^2 + 18x + 24 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 3, b = 18, and c = 24.

Substituting these values into the formula, we get:

x = (-18 ± √(18^2 - 4(3)(24))) / (2(3))

Simplifying further:

x = (-18 ± √(324 - 288)) / 6
x = (-18 ± √36) / 6
x = (-18 ± 6) / 6

This gives us two solutions:

x = (-18 + 6) / 6 = -12/6 = -2
x = (-18 - 6) / 6 = -24/6 = -4

So the solutions to the equation 3x^2 + 18x + 24 = 0 are x = -2 and x = -4.