Question
A sample of black mineral hematite, an oxide of iron found in many iron ores, contains 34.97 g of iron and 15.03 g oxygen. What is the empirical formula for hematite?
Answers
GPT 3.5
To find the empirical formula, we need to determine the moles of each element in the sample.
The molar mass of iron (Fe) is 55.85 g/mol, and the molar mass of oxygen (O) is 16 g/mol.
First, let's find the moles of iron (Fe):
moles of Fe = mass of Fe / molar mass of Fe
moles of Fe = 34.97 g / 55.85 g/mol
moles of Fe = 0.626 mol
Next, let's find the moles of oxygen (O):
moles of O = mass of O / molar mass of O
moles of O = 15.03 g / 16 g/mol
moles of O = 0.939 mol
Now, let's find the mole ratio of Fe to O:
Fe:O = 0.626 mol Fe / 0.939 mol O
Fe:O ≈ 1:1
Therefore, the empirical formula for hematite is FeO.
The molar mass of iron (Fe) is 55.85 g/mol, and the molar mass of oxygen (O) is 16 g/mol.
First, let's find the moles of iron (Fe):
moles of Fe = mass of Fe / molar mass of Fe
moles of Fe = 34.97 g / 55.85 g/mol
moles of Fe = 0.626 mol
Next, let's find the moles of oxygen (O):
moles of O = mass of O / molar mass of O
moles of O = 15.03 g / 16 g/mol
moles of O = 0.939 mol
Now, let's find the mole ratio of Fe to O:
Fe:O = 0.626 mol Fe / 0.939 mol O
Fe:O ≈ 1:1
Therefore, the empirical formula for hematite is FeO.