Question
Solve the following quadratic equation using square roots:
-9+ (x-3)^
__________ =-4
-4
-9+ (x-3)^
__________ =-4
-4
Answers
Answered by
GPT 3.5
To solve the quadratic equation using square roots, we will isolate the square term and square root both sides of the equation.
Starting with the given equation:
-9 + (x-3)^2 / -4 = -4
First, multiply both sides of the equation by -4 to eliminate the fraction:
-4(-9 + (x-3)^2 / -4) = -4(-4)
Expand the equation:
36 - (x-3)^2 = 16
Next, add (x-3)^2 to both sides of the equation to isolate the square term:
36 - (x-3)^2 + (x-3)^2 = 16 + (x-3)^2
Simplify:
36 = 16 + (x-3)^2
Subtract 16 from both sides of the equation:
20 = (x-3)^2
To eliminate the square, we take the square root of both sides:
±√(20) = ±√((x-3)^2)
Since we are looking for real solutions to the quadratic equation, we only consider the positive square root:
√20 = x - 3
Simplify the square root:
√4 * √5 = x - 3
Simplify further:
2√5 = x - 3
Finally, isolate x by adding 3 to both sides of the equation:
2√5 + 3 = x
Therefore, the solution to the quadratic equation is:
x = 2√5 + 3.
Starting with the given equation:
-9 + (x-3)^2 / -4 = -4
First, multiply both sides of the equation by -4 to eliminate the fraction:
-4(-9 + (x-3)^2 / -4) = -4(-4)
Expand the equation:
36 - (x-3)^2 = 16
Next, add (x-3)^2 to both sides of the equation to isolate the square term:
36 - (x-3)^2 + (x-3)^2 = 16 + (x-3)^2
Simplify:
36 = 16 + (x-3)^2
Subtract 16 from both sides of the equation:
20 = (x-3)^2
To eliminate the square, we take the square root of both sides:
±√(20) = ±√((x-3)^2)
Since we are looking for real solutions to the quadratic equation, we only consider the positive square root:
√20 = x - 3
Simplify the square root:
√4 * √5 = x - 3
Simplify further:
2√5 = x - 3
Finally, isolate x by adding 3 to both sides of the equation:
2√5 + 3 = x
Therefore, the solution to the quadratic equation is:
x = 2√5 + 3.