To find the equation of the line that contains the new wall, we first need to find the slope of the original wall. The equation given, y = 3x + 2, is already in slope-intercept form (y = mx + b) where the coefficient of x is the slope. Therefore, the slope of the original wall is 3.
Since the new wall is perpendicular to the original wall, the slopes of the two walls must be negative reciprocals of each other. Therefore, the slope of the new wall is -1/3.
We can use the point-slope form of a linear equation to find the equation of the new wall. Plugging in the values, we have:
y - (-8) = (-1/3)(x - 6)
Simplifying,
y + 8 = -(1/3)(x - 6)
y + 8 = -(1/3)x + 2
y = -(1/3)x + 2 - 8
y = -(1/3)x - 6
Therefore, the equation of the line that contains the new wall is y = -(1/3)x - 6.
The correct answer is: y = -(1/3)x - 6.
Plans for a stadium are drawn on a coordinate grid. One wall lies on the line y = 3x + 2. A perpendicular wall passes through the point (6, -8.) Write the equation of the line that contains the new wall. (1 point) Responses
y=−13x−6
y=3x−26
y=13x−10
y=−3x−14
1 answer