Find the normality of 0.321 g sodium carbonate in a 250 mL solution.

Answer 1

To find the normality of a solution, we need to know the number of moles of the solute present in the given volume.

First, we need to calculate the number of moles of sodium carbonate.
The molar mass of sodium carbonate (Na2CO3) is:
Na: 22.99 g/mol
C: 12.01 g/mol
O: 16.00 g/mol

To calculate the molar mass of sodium carbonate:
(2 × 22.99 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol) = 46.00 g/mol + 12.01 g/mol + 48.00 g/mol = 106.01 g/mol

Next, we convert the given mass of sodium carbonate (0.321 g) to moles using the molar mass:
0.321 g / 106.01 g/mol = 0.00303 mol

Now, we need to find the number of moles in the given volume.
The volume is given as 250 mL, but we need to convert it to liters:
250 mL = 250 mL / 1000 mL/L = 0.25 L

Finally, we can calculate the normality by dividing the number of moles by the volume in liters:
Normality = 0.00303 mol / 0.25 L ≈ 0.0121 N

Therefore, the normality of the solution is 0.0121 N.